The sample space has 36 elements (the total number of outcomes by rolling the two dice).
There are 6 double outcomes: (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6).
There are 5 outcomes whose sum is 6: (1,5), (5,1), (2,4), (4, 2), and (3,3).
The probability of rolling doubles OR the sum of 6 is 6/36 + 5/36 = 11/36.
If two fair dice were rolled, there would be 36 outcomes. (1,1),(1,2),....,(6,6) The maximum sum would be 12. Therefore, the probability that the total number of spots shown is equal to 15 is zero.
The probability of not rolling a number larger than 4 is the probability of rolling a number equal to 4 or lower: P(x≤4) = P(1) + P(2) + P(3) + P(4) = 4/6 = 2/3 = 0.6666... ≈ 66.7%
For 6 sided dice, there is only 1 way to get a 2: (1,1). There are 36 outcomes rolling 2 dice; so the probability of rolling two numbers whose sum is 2 is 1/36.
Assuming that there are an equal number of even and odd faces on the eight-sided die, then the probability of rolling an even number is simply 4 in 8, or 1 in 2, or 0.5.
Each of the dice has 6 sides. There are 6 x 6 = 36 possible combinations. Of those, the following equal 5: 1 and 4 2 and 3 3 and 2 4 and 1 So the odds of rolling a 5 is 4 chances out of 36 4 / 36 = 1 / 9 That converts to a probability of 0.1111111...
It is 1.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
the answer is 4
The probability to get a 12, with two dice, is 1/36.
It is 1/3
For a 6 sided die, each number 1 - 6 has equal probability. So, probability of rolling a 5 is 1/6.
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
The answer depends on what you are rolling: a number cube or some other shape? For a die, the answer is 2/3.
If two fair dice were rolled, there would be 36 outcomes. (1,1),(1,2),....,(6,6) The maximum sum would be 12. Therefore, the probability that the total number of spots shown is equal to 15 is zero.
6/36 which is equal to 1/6
Since all numbers on a die are 6 or below, the probability is 6/6, 1, or 100%.
The probability of not rolling a number larger than 4 is the probability of rolling a number equal to 4 or lower: P(x≤4) = P(1) + P(2) + P(3) + P(4) = 4/6 = 2/3 = 0.6666... ≈ 66.7%