It isnt, There is a 50/50 chance on getting a head or either a tail, as there are 2 sides as it has 2 faces. I hope this helped :D X
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Because you are thinking permutations rather than combinations. There are four permutations of two coins, but there are only three combinations, because it does not matter which coin is heads and which coin is tails. As a result, the combination of heads and tails has a 0.5 probability, while two heads or two tails each have a 0.25 probability.
Actually, although it may seem like it, it is not 50-50. The answer's more like 55-45 This is because the 'head' side is heavier than the 'tails' side. So it is more likely to be tails 3 heads 1
If 10 coins are tossed, you could get 4 heads and 6 tails, 3 heads and 7 tails, 2 heads and 1 tail, 0 heads and 10 tails all giving fewer heads than tails. Using the binomial distribution , P(4 heads) = 10C4 (.5)^4 (.5)^6 = 0.205078. P(3 heads) = 10C3 (.5)^3 (.5)^7 = 0.117188 P(2 heads) = 10C2 (.5)^2 (.5)^8 = 0.043945 P(1 heads) = 10C1 (.5)^1 (.5)^9 = 0.009766 P(0 heads) =(.5)^10 = 0.000977 Adding all of these probabilities, we have P(fewer heads than tails)= 0.376953
The probability of heads is 0.5 or 1/2. This is wrong, the chances of a penny landing heads up is less than 0.5 because the cast in Lincoln's head weighs more than the tails side of the peeny.
Less. The more times the coin is tossed, the more likely it will reflect the actual odds of .5 heads and .5 tails.