Write a program to find the value the integration 1by1plus X between the limits 0 and 1 through trapezoidal rule?

Answer 1

#include<stdio.h>

#include<conio.h>

#include<math.h>

float f(float x)

{

float y;

if(x!=0)

//y=sin(x)-log(x)+exp(x);

y=1/(1+x);

else

printf("answer can not be derived");

return(y);

}

float g(float x)

{

float k;

k=(-2)/(pow((1+x),3));

return(k);

}

void main()

{

float i,n,k,z,s=0,err=0;

float h,x,a[100],b,c;

clrscr();

printf("\n enter the range of the integration");

scanf("%f%f",&b,&c);

printf("\n enter n so to divide the range into n parts");

scanf("%f",&n);

h=(c-b)/n;

printf("\n\n%f",h);

k=(f(b)+f(c));

printf("\nk=%f\n\n",k);

for(i=b+h;i<c;i+=h)

{

z+=f(i);

printf("\n%f",z);

}

s=(h*(k+2*z))/2;

printf("\n\n the value of the integration=%f\n\n",s);

for(i=b;i<=c;i+=h)

err+=g(i);

err=(err*(pow(h,3)))/12;

printf("\n\n approximate error= %f\n\n",err);

getch(); }here...