When you say three out of five I'm assuming you mean three wins out of five games. If that is the case, then 54 games out of 90 would have been won.
It's possible. All teams would have to win all home or away games and lose all away or home games.
In 2008, the only team to lose 16 games were the, Detroit Lions. They finished that 2008 season with an 0-16 record.
The Chiefs can clinch their division by winning their remaining games and having other teams in their division lose enough games for the Chiefs to secure a better overall record.
No, the fewest losses in a season for an MLB team is 36 by the 1906 Chicago Cubs (record was 116-36).
Yes they did. Their record that year was 0-16 making them the first NFL team to lose 16 games in a season. Other NFL Teams had gone winless before but never during a 16 game schedule.
assuming there were no draws then the win to lose ratio is 3:4
Depends, if the Yankees win, then the rays lose the division. However if both teams lose then it will be a tie which should be decided by the season record between the 2
The first four teams to be eliminated in March Madness are typically the teams that lose in the First Four games, which are played before the main tournament begins. These games involve the lowest-seeded teams and determine which teams advance to the main bracket.
No, in order to make it to the Super Bowl both teams must win all of their playoff games.
There will be 94 games. If a tournament is single elimination, the number of games will always be one less than the number of teams. This is because all teams must lose one game, except for the champion.
That depends on how many games the other playoff contenders have won.
The Yankees record in 2007 was 94-68.