How do you serparate 9 Marbles into 4 Boxes All nine marbles must be used and each box must have an odd number of marbles?

How many boxes do you need for 379 marbles?

That's going to depend on both the size of the marbles and the size of the box.

If Jill Places 3 red and 3 green marbles in 2 boxes then bill comes in and picks a marble out of one box To win he needs a red Marble How should Jill place the marbles to give bill the best chance?

If you place 3 marbles in each box then the probability is always one half or 50%. If you do not put exactly 3 marbles in each box, the probability will become less than 50%. It does not matter what colors of marbles you put in each box.

How will you put twentyone marbles in four boxes using odd number without repetition?

it's impossible because the sum of any two odd numbers equals an even number; odd# + odd# = even#. even# +even# = even#. odd# + odd# + odd# + odd# = even#.

How do you calculate the max number of boxes on a palett?

# of boxes height wise times the # of boxes width. If it is 5 boxes high and 5 boxes wide then you would have 25 boxes on that pallet.

How much do boxes for moving cost?

Moving boxes and moving boxes packages can cost between $50- $125 for an average sized move. The cost of moving boxes varies depending on the number of rooms you are moving. Free boxes are available from a number of sources!

What are some common items used for centerpieces for weddings?

There are so many options to chose from. Here are some of the most common centerpieces for weddings. Flowers, candles, bowls filled with marbles or glass spheres of assorted colors as well as bowls filled with water that contain floating rose petals or floating candles, some arrangements include picture frame boxes or small dishes with assorted chocolates and candies.

How do you answer the question . Number of pencils equals number of boxes how many pencils in 18 boxes?

I don't think you have enough information to answer that question.

Math sample papers -math olympaid?

These questions are from the Australasian Maths Olympiad Website.http://www.apsmo.info/APSMO_Home.phpA. (Time: 3 minutes)What is the value of:268 + 1375 + 6179 - 168 - 1275 - 6079 ?B. (Time: 5 minutes)Each of 8 boxes contains one or more marbles. Each box contains a different number of marbles, except for two boxes which contain the same number of marbles. What is the smallest total number of marbles that the 8 boxes could contain?C. (Time: 5 minutes)Find the whole number which is:less than 100;a multiple of 3;a multiple of 5;odd, and such that,the sum of its digits is odd.D. (Time: 6 minutes)Takeru has four 1 centimetre long blocks, three 5 centimetre long blocks, and three 25 centimetre long blocks. By joining these blocks to make different total lengths, how many different lengths of at least 1 centimetre can Takeru make?E. (Time: 6 minutes)The figure below is made up of 5 congruent squares. The perimeter of the figure is 72 cm. Find the number of square cm in the area of the figure.AnswersA. - 300METHOD 1: Make a simpler problem...Notice that each number being added is 100 more than one of the numbers being subtracted.The value is 100 + 100 + 100 = 300METHOD 2: Group by operation...Add the numbers 268 + 1375 + 6179 = 7822.Then add the numbers 168 + 1275 + 6079 = 7522.Finally, subtract the totals: 7822 - 7522 = 300B. - 29 marblesDraw a picture...Draw 8 boxes. Then put the smallest possible number of marbles in each box. Put 1 marble in box 1. Then put 1 marble in box 2. You can't just put 1 marble in box 3, because that would make three boxes with the same number of marbles. So put 2 marbles in box 3, 3 marbles in box 4, and so on.The smallest total number of marbles is 1+ 1 + 2 + 3 + 4 + 5 + 6 + 7 = 29 marbles.C. - 45Proceed one statement at a time. Eliminate those numbers which fail to satisfy all the conditions.WHOLE NUMBERS THAT SATISFY ALL CONDITIONSLess than 100 1, 2, 3, ..., 99Multiple of 3 3, 6, 9, ..., 99Also multiple of 5 15, 30, 45, 75, 90Odd 15, 45, 75Sum of digits is odd 45D. - 79METHOD 1: Start with a simpler problem...(a) Lengths formed by 1 cm blocks: 1, 2, 3, 4.(b) Lengths formed by remaining blocks: 5, 10, 15; 25, 30, 35, 40; 50, 55, 60, 65; 75, 80, 85, 90.(c) Each of the fifteen (b) length bocks can be combined with the four (a) lengths, thus producing 15 x 4 = 60 different amounts.TOTAL AMOUNTS:(a) 4(b) 15(c) 60GRAND TOTAL:79 different amountsMETHOD 2Number of choices for 1cm lengths, including 0, is 5: (0, 1, 2, 3, 4).Number of choices for 5cm lengths, including 0, is 4: (0, 1, 2, 3).Number of chioces for 25cm lengths, including 0, is 4: (0, 1, 2, 3).Total number of choices for all lengths is 5 x 4 x 4 = 80. However, 80 includes the choice of having none of the lengths as a choice. Since it is given that each length must be 1cm or longer, there are 80 - 1 = 79 amounts of at least 1cm.METHOD 3: Establish a maximum and then eliminate all impossibilities.Find that largest possible length that can be made with the blocks, and then subtract the number of smaller values that cannot be made. The maximum that can be made is 4 + 15 + 75 = 94cm. The 15 lengths less than 94cm that cannot be made are those that require four 5cm blocks. These are 20, 21, 22, 23, 24, 45, 46, 47, 48, 49, 70, 71, 72, 73 and 74cm lengths. The number of possible lengths is 94 - 15 = 79E. - 180 cm²Find the length of one side of the figure...Because of the common dies, all the squares are congruent to each other. The perimeter consists of 12 equal sides. The length of a side is 72 / 12 = 6cm. The area of each square is 6 x 6 = 36cm².The area of the figure is 5 x 36 = 180cm².You can buy Maths Olympiad BooksMATHS OLYMPIAD CONTEST PROBLEMSby Dr George Lenchner(Australian Edition. 2005. Reprinted with corrections 2008.)285 pagesISBN : 978-0-9757316-0-4MATHS OLYMPIAD CONTEST PROBLEMS Volume 2(Australian Edition. 2008.)Editors : R. Kalman, J. Phegan, A. Prescott320 pagesISBN : 978-0-9757316-2-8CREATIVE PROBLEM SOLVING IN SCHOOL MATHEMATICSby Dr George Lenchner(Australian Edition. 2006.)290 pagesISBN : 978-0-9757316-1-1

If I have 14 sponges and there are s boxes write an equation that shows how many packages I have.?

It is not possible to answer the question because there is no relation between the sponges and boxes, the sponges and packages and boxes and packages.

How many boxes in a twenty foot container?

The number of boxes that can fit in a 20-foot contain can vary a bit by the size of the boxes. Anywhere from 700 to 1000 boxes is average.

What does it mean when you multiply a number times more than it does for example....... Yoshi has 25 boxes alice has 5 times more boxes than him how much boxes alice has?

Alice has 5*25 boxes = 125 boxes

A store sells boxes of juice in equal-size packs. Garth bought 18 boxes Rico bought 36 boxes and Mia bought 45 boxes What is the greatest number of boxes in each pack?

9