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How many 3-letter code words are possible using the first 8 letters of the alphabet if no letter can be repeated?
Wiki User
∙ 13y ago
-4
Benny Wuckert
Bailee Jacobi
-5
Wiki User
∙ 13y agoThis would be a permutation.
26*25*24=15600
or
n!/(n-r)! where n=26 and r=3
so you get...
26!/(26-3)! = 26!/34! =
(26*25*24*23*22*21*20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3)/ (23*22*21*20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3)
=15600
Wiki User
∙ 13y ago6, dab, cab, bag, fed, beg, and bag
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