8 = 2 cubed
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∙ 14y ago(c + 8)(c - 8)= c^2 - 64
MEAN = ( 8+10 )/2 = 18/2 =9
depends, when c>0, yes. when c=0 it's equal 4*0=0 and when c<0 it is smaller, because c=4: 4*-2=-8 and -8 is smaller than -2
28 1 2 3 4 -------------------| 5 | 6 | 7 -------------------- 8 1 clicks 7 times 2 clicks 6 3 clicks 5 4 c 4 5 c 3 6 c 2 7 c 1 8 c 0 ______ 28
Let the angle opposite to the side of 6 be C, then cos C = (7^2 + 8^2 - 6^2)/(2 x 7 x 8) cos C = 77/112 cos C = 0.6875 m of C = arc cosine(0.6875) = 46.57 degrees
If you mean to divide 2 by the fraction 7/8, that is the same as multiplying with the reciprocal: 2 x 8/7.If you mean to divide 2 by the fraction 7/8, that is the same as multiplying with the reciprocal: 2 x 8/7.If you mean to divide 2 by the fraction 7/8, that is the same as multiplying with the reciprocal: 2 x 8/7.If you mean to divide 2 by the fraction 7/8, that is the same as multiplying with the reciprocal: 2 x 8/7.
Mean: 3 I think the range is 7 or 8
You need to use the pythagorean theorem to answer this question. a^2+b^2=c^2 In this case, you know the length of 2 legs. (a and b)... you are trying to solve for c ( the hypotenuse)... so.. 6^2+8^2=c^2... solve for c... 36+64=100... take the square root of 100, and c=10!
2 covers on a book
y = mx + c Here y = -4x + c Since it passes through -2, 3 3 = (-4)(-2) + c 3 = 8 + c 3 - 8 = c c = -5 Hence equation is y = -4x -5
Geometric mean = √(2 x sqrt(8)) = 2.37841 (rounded)
Pythagorean theorem. a^2 + b^2 = c^2. Base divide by 2 = 6 which is the base for each of half of this triangle. Thus 6^2 + 8^2 = c^2. C= 10. The Length of each of the two legs is 10.