16
(c + 8)(c - 8)= c^2 - 64
2. c2 + c2 + 8 = 8c 2c2 - 8c + 8 = 0 c2 - 4c + 4 = 0 (c - 2)(c - 2) = 0 (c - 2)2 = 0 c - 2 = 0 c = 2
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
a=-2 4b=-2 --> b=-1/2 c=8 (-2)(-1/2)(8)(3)= 24
C=20
c^2 + c - 56 = (c - 7)(c + 8) using the factoring rule: c -7 -7c x x + c 8 8c c^2 -56 c
8
If by ' A 64 pi' you mean the Area. Then A = 64pi Since A = pi r^2 and 64 is 8^2 Then we can say r(radius)= 8 The circumference of a circle is C = 2pir Hence C = 2 x 3.14 x 8 C = 16 x 3.14 C = 50.24 linear units. The value for 'pi' at 3.14 is an approximation.
using the pythagorean thereom. a^2 + b^2 = c^2 in which a and b are your legs and c is your hypotenuse 8^2 + 15^2 = c^2 289=c^2 17 is the hypotenuse
Studio C - 2012 2-8 was released on: USA: 21 May 2013
MEAN = ( 8+10 )/2 = 18/2 =9