8 out of 12.
Simplified, it's 2 out of 3.
P(B) = 0.12 = 12%There are 25 pair of socks: 10 Black, 12 White, 3 Brown.P(B) = 3/25 = 0.12 = 12.0%
100% She will either have at least two brown socks or two white socks in any scenario.
75%
I assume you are selecting two socks (one at a time) from the drawer to wear (for example). There are 6 white + 3 black + 3 brown + 8 gray = 20 socks in all So the probability that the first sock chosen to be white is 6/20 since there are 6 socks and 20 socks in total. 6/20 reduces down to 3/10. The probability that the second sock chosen is also white is 5/19 since there are now only 5 white socks left to be chosen and 19 socks in total (since one sock has been taken out). Thus the probability of both socks being white is: probability = 3/10 x 5/19 = 3/38
75%
The probability that he or she will have brown eyes and blond hair is 21/50.
3
28
The answer depends on where on earth the street is. In a village in much of Asia or Africa, I suggest the probability is 0.
In this case, it doesn't matter what the genotype of the other parent is since BB is homozygous dominant (assuming this is the only gene that affects coat colour of course). All of the BB parent's offspring will PHENOTYPICALLY be brown-coated. They may be heterozygous though (Bb) depending on genotype of the second parent. So the PHENOTYPIC probability of a brown coat is 100% The genotypic probability of a homozygous genotype depends on the second parent.
Depends on the parents.
You must remove 12 socks to be sure of having a pair of Brown one