You're living dangerously.
If the averages don't have equal weight, your average of averages will yield skewed results. Here's why.
Let's say you're trying to calculate your overall average grade for all the tests you've taken in school, and let's say you are taking only math, English, and science. Let's say your average in math is 80, English is 85, and science is 90. The average of those averages is, of course, 85. But is that your true average?
Not if you took ten math tests, five English tests, and only two science tests!! If all those tests have equal value, then your average is closer to 80, because the ten math tests dominate the true average. In other words, your true average is the WEIGHTED average of the three averages. To weight them properly, you must think of the math average as not one data point but ten data points, the English average as not one data point but five, and the science average as not one but two data points.
Here's how the weighted average math looks:
10 x 80 = 800
5 x 85 = 425
2 x 90 = 180
__ ___
17 1405
Now, divide 1405 by 17. So, 1405/17 = 82.7. (The 17 is the sum of the weighting factors, which, as you can see, is equal to the total number of tests you took.)
So, you can see that taking the average of averages may give erroneous results -- unless you find the weighted average.
No, a sum of averages is NOT as accurate as the average of the whole. For example: A=avg (1,10) = 5.5 B=avg (1, 1, 1, 1, 1) = 1 avg(A,B) = 3.25 [Average of averages] avg(1,1,1,1,1,1,10) = 2.29 [The original data set]
You can get the average of an average, but you would be averaging one number, so you would get the same result. You can get the average of a set of averages, though to make sense they will often need to be a weighted average of averages.
Moving averages. And even then, they are not that good.
I recommend you do not try to average a set of components, because your result may be not be accurate. The best way to find an overall average is to average the entire data set.EXAMPLE: You have three columns of ten numbers each with an average listed at the bottom of each, say A11, B11, and C11. There are two ways you can solve this:Combine all the averages and divide by 3. [=SUM(A11:C11)/3] - But, the result may not reflect the average of the entire data set.Calbulate the average for all 30 numbers in the data set. [=SUM(A1:C10)/30] - This would give a much more accurate representation of the entire data set.
It is also an average. It is usually a better measure of the average value of the characteristic that is being measured.
Average = Total/Count so Total = Average*Count.
He has many averages, but yes this is one of them.
The average surface temperature of a venue can vary widely depending on factors such as location, time of year, and weather conditions. It is recommended to check local weather data or historical averages for a more accurate estimate.
A Mean is a type of average, but there are other kinds of averages too, Modes and Medians.
an average is the most frequent number (or result) in a set of data.
4.5mm
It averages 44 inches per year.