Approx 3.26 km.
Pancakes, because astronauts only kayak with pineapples.
An airplane flying at an altitude of 2600m, approaching an airport runaway located 48km away, is descending at an angle of 3.1 degrees, rounded to the nearest tenth of a degree. Construct a right triangle. Horizontal is 48. Verticle (opposite) is 2.6. Hypoteneuse is 48.07 by pythagorean theorem. The inverse sine of (2.6 / 48.07) is 3.1 degrees.
When a plane takes off it travels for a horizontal distance of 1400 ft before reaching its maximum altitude of 50000 ft; the plane's angle of elevation as it rises would be 86 degrees.
It depends on your latitude. At the equator (0 degrees) a degree of longitude covers just over 111 km, so 8 degrees would be about 890 km. At 45 degrees of latitude, a degree of longitude covers just under 79 km, so 8 degress would be about 555 km. Check out the calculator in the related link. Enter the degrees of latitude and it gives the length of a degree at that point.
Yes because they add up to 180 degrees
the temperature in the atmosphere approaches -90 degrees Celsius at an altitude of about answer is 80 kilometers
azimuth 100 degrees altitude 20 degrees
The coordinate S 20 E 130 is located 29.7 kilometers east of Tanami, NT, Australia. It has an altitude of about 1204 feet above sea level.
Zero.
66.5 degrees
First, we need the "transit altitude" of the celestial equator, at 80 degrees north. That's 90 - 80 degrees = 10 degrees. At noon (local apparent noon) the Sun's altitude will be: 10 degrees + the Sun's declination. That's the altitude of the Sun's "upper culmination". At "midnight" (the Sun's "lower culmination") the Sun's altitude will be: the Sun's declination - 10 degrees. So, the difference in altitude is 20 degrees. The Sun is 20 degrees higher at noon.
zero = horizon
0 Degrees
43 degrees because the altitude of polaris is equal to the latitude of utica.
The star is at an altitude of 15 degrees above the horizon at midnight.
An object seen halfway between the horizon and the zenith has an altitude of 45 degrees.An object seen due east of the observer has an azimuth of 90 degrees.
The boundary between the stratosphere and the mesosphere located at an altitude of about 55 kilometers (35 miles) above the earth's surface.