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How do you find center of a circle given 3 points on the circle?
Wiki User
∙ 8y ago
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
Wiki User
∙ 8y ago
Wiki User
∙ 9y agoLabel the three points A, B and C. Construct the perpendicular bisector of any two of AB, BC and CA. They will meet at the centre of the circle. You could draw the perpendicular bisector of the third chord as a check that is also goes through the same point..
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How would you explain how to find sine and cosine within each quadrant of a unit circle?
To find the sin/cos at a given point on the unit circle, draw a radius to that point. Then break the radius into components - one completely horizontal and one completely vertical. The sine is the vertical component, the cosine is the horizontal component.
How do you find a slope of a line?
That depends upon what you are given - the equation of the line, the coordinates of 2 points on the line, etc.
How do you find angle on triangle?
Given only the information provided in the question, the answer is to measure it.
What can you solve in the Pythagorean theorem?
Given the lengths of two sides of a right triangle, you can find the length of the other side.
How do you find the hypotenuse of a right triangle when only a side length and angle is given?
Dependent on what side you are given you would use Sin(Θ) = Opposite/Hypotenuse just rearrange the formula to Hypotenuse = Opposite/Sin(Θ). Or if you are given the adjacent side use Cosine(Θ)=Adjacent/Hypotenuse, then: Hypotenuse = Adjacent/Cosine(Θ)
How do you find the center of a circle with two given points?
If you're only given two points, and you're told that they both lie on a circle,then there are an infinite number of possible circles, and therefore an infinitenumber of possible centers. In order to pin it down, you need three points.
How do you find the center or midpoint of a circle given one endpoint of the diameter?
to be honest I dont know
What is a center coordinate of 2 points known circle?
Knowing two points on a circle does not define a unique circle, so it is impossible to find the centre of the circle as there are infinitely many centres possible.
How to find the radius of a circle?
divide the diameter(the length of a straight line passing through the center of a circle and connecting two points on the circumference)by 2
What is the answer A circle of center (-3 -2) passes through the points (0 -6) and (A 0). Find A.?
The value of A works out as -7.582575695 because both points will have an equal distance of 5 units from the center of the circle (-3, -2)
Does a circle have an area?
A circle *encloses* an area, and the "area of a circle" is the area it encloses, πr^2. A circle is a 1-dimensional curved line; it is a set of points equidistant from a given point (the center), with that distance being the radius of the circle. This means the inside of the circle is not part of the circle (it's called a disk if you include the inside points).To find the area, multiply pi (π) by the radius squared (r^2), so you get πr^2.Yes, it does.
How do you work out the radius of a circle without knowing the area?
This depends on what information you are given.If you have the circumference of the circle, you know that:c = 2πr∴ r = c / 2πIf you have the diameter of the circle, it's radius is half of that:r = d/2If you are given any three points on the circle's perimeter, you can use those to find the radius. This can be done with the following steps:Take any two of those three points, and find both their halfway point and the slope of the line on which they lie.With those, work out the equation for a line that passes through that halfway point, and is perpendicular to the line on which those points lie.Repeat those two steps with any other two of the three points .With the two lines you now have, find their point of intersection. That will be the center of the circle.Now find the distance from that center point, to any one of your three given points. That is the circle's radius.Also, if you have an equation for the circle, then you can work it out that way. The equation would need to be rearranged into the format (x - a)2 + (y - b)2 = r2. The last variable, "r", is your radius.
How do you find radius of a circle?
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
How do you find the centre of a circle given part of a radius?
You would have to know the length of the radius. The center of the circle is at one end of the radius. If you just know where some part of the radius is, and not that the part touches the circle then you cannot know where the center is without at lest a point on the circumference.
Where do you find the radius?
A radius is the distance from the center point of a circle to the outside. To find the radius, you'd draw a line from the center of a circle straight out until it hits the circle itself, then measure the length of the line you just drew. If you are given a diagram where only the diameter is shown (the distance from one side of the circle to the other), just take half the diameter.
How do you find the radius of the circle when you know the center and a point on the circle?
measure it
How many circles can pass through two given points?
It takes 3 non collinear points to define one specific circle. With only two points an infinite number of circles can be drawn. Proof: Given two points A, B draw the line between them. Then find the perpendicular bisector of the line AB. Any point on the perpendicular bisector is equidistant from the two original points, A and B. A circle with center C and radius AC will then pass through points A and B. There are infinite point C's on the perpendicular bisector so there are infinite circles. Given three points A, B and D you can find the perpendicular bisector for line segements AB and then the perpendicular bisector fof line segment BC. The two perpedicular bisectors will not be parallel because the points A, B and D are non collinear. This means the two perpeniducar bisectors will intercept at only one point C(like any two intercepting lines). This point C is equidistant from points A, B, and D. A circle with center C and radius AC will then pass through all three of the points. Since there is only one point C that lies on both perpendicular bisectors, there is only one circle possible.
