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Very simple! You need a square piece of cardboard. (make sure it is a perfect square)
And also make four small triangles and one square that fit within the large square.
I have put a link to a picture of what you have to make in the sources box. Label the sides of the peices as I have in the diagram. Sorry the drawings so wonky.
The diagram shows a square of side length c inside another square of side length a + b.
The area of the large square can be written as (a + b)^2 or c^2 + 2ab (the area of the small square plus the four triangles).
There for (a+b)^2= c^2+2ab
expand a^2+2ab+b^2=c^2+2ab
Subtract 2ab from both sides and you have a^2 + b^2 = c^2
The model then proves pythagoras's theorem.
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How do you make a working model on Pythagoras theorem?
You can draw it on paper. Not sure what you mean with "working model": this is not about a physical device. Pythagoras' Theorem is about one specific type of calculatoin.
When did Pythagoras make his theorem?
he discovered it in 196C
How do you make Pythagoras theoram?
By constructing a right angle triangle whereas its hypotenuse when squared is equal to the sum of its squared sides which is known as Pythagoras' theorem.
How do you make Pythagoras theorem model?
First construct a right angle triangle with dimensions of: base = 3 units, height = 4 units and hypotenuse = 5 units Then construct 3 exterior squares on each of the sides with the given dimensions. Sub-divide these squares into smaller squares so that the base has 9, the height has 16 and the hypotenuse has 25 Pythagoras' theorem says: base2+height2 = hypotenuse2 Congratulations, your visual model proves that this is true.
What is Pythagoras thesis?
I have attached a link of the first hit on google. I don't know how trustworthy it is but anyway (because I'm not sure if you meant theorem, and also it would be a misinterpretation of the word thesis, i.e. true and proven). Pythagoras' Theorem on the other hand is that with a right angled triangle, the lengths of the two sides that make the right angle squared and added together gives the square of the length of the third side (opposite the right angle)
