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This answer uses trigonometry to avoid a lot of work:

tangent = opposite/adjacent and tangent*adjacent (base of ladder from the building) = opposite (height of ladder above ground)

So: tangent 60 degrees*3 = 5.196152423

Therefore: Top of the ladder above ground = 5.2 meters correct to one decimal place.

More laborious methodThe right triangle formed by the wall, ground and ladder has sides in the ratio of 1::2::sq-rt-of-3.

The shortest side is the one opposite the 30 degree angle, i.e., the given distance from wall to base of the ladder--3 m.

The length of the ladder represents the hypotenuse of the triangle, and is twice as long, hence 6 m.

And the height of the ladder's top from the ground is proportional to the third side whose length is sq-rt-3 times that of the shortest side. Sq-rt-3 is about 1.732, so height of the ladder's top at the wall is about 5.20 m, or 520 cm.

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Q: If A ladder leaning against a wall makes a 60 angle with the ground the base of the ladder is 3 m from the building how high above the ground is the top of the ladder?
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