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In a triangle ABC b equals 15 cm and c equals 25 cm and also angle B equals 32'15'Find the side a and other angles?
Wiki User
∙ 10y ago
By the sine rule,
sin(C)/c = sin(B)/b
so sin(C) = 25/15*sin(32d15m) = 0.8894
so C = 62.8 deg or 117.2 deg.
Therefore, A = 180 - (B+C) = 85.0 deg or 30.5 deg
and then, using the sine rule again,
a/sin(A) = b/sin(B)
so a = sin(A)*b/sin(B) = 28 or a = 14.3
Wiki User
∙ 10y ago
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