The answer depends on the shape of the can. You can get thin tall cans, or wider short cans.
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To answer this question more information is needed. What dimensions, what material, where is it fitted, how secure must it be, etc.
First construct a right angle triangle with dimensions of: base = 3 units, height = 4 units and hypotenuse = 5 units Then construct 3 exterior squares on each of the sides with the given dimensions. Sub-divide these squares into smaller squares so that the base has 9, the height has 16 and the hypotenuse has 25 Pythagoras' theorem says: base2+height2 = hypotenuse2 Congratulations, your visual model proves that this is true.
Yes because the given dimensions comply with Pythagoras; theorem for a right angle triangle.
d2 = a2 + b2 + c2 a, b, and c are dimensional distances which are perpendicular (like x, y, and z coordinate system) and d is the distance between 2 points separated by those dimensions (or a diagonal line between the 2 points).
A "tread" and a "run" are the same thing. Your question negates itself. However, if what you meant was an 11" riser and a 7" tread, then what you are describing is a ladder, as it would have an angle greater than 50 degrees. Ideally, you should reverse the dimensions, in which case then, yes, a 1" overhang is appropriate.