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To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...

sin2(theta) + cos2(theta) = 1

... and then solve for the question...


cos2(theta) = 1 - sin2(theta)

2 cos2(theta) = 1 - sin2(theta) + cos2(theta)

2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)

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Q: What does negative sine squared plus cosine squared equal?
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Continue Learning about Trigonometry

What is 1 plus cotangent squared?

1 + cot2x = csc2x


What is Pythagoras famous quotes?

a2+b2=c2 a squared plus b squared equals c squared


What is the equation for Pythagoras therum?

a squared plus b squared equals c squared.example: a=5 5sq is 25 b=8 bsq is 64 64+25 or a squared + b squared=89. then you find the square root of 89 and there's your answer. 9.4 [rounded]


Why does sin theta squared plus cos theta squared equal 1?

Sin2(theta) + cos2(theta) = 1 for the same reason that the sides of a right triangle squared equal the hypotenuse squared - The pythagorean theorem.In the unit circle (origin = (0,0), radius = 1), an angle theta is the angle made by some arbitrary ray drawn from the origin at an angle relative to the x axis. The point of that ray that intersects with the circle is the point (x,y).Sin(theta) is defined as x, and cos(theta) is defined as y. These are primary trigonometric identities, which link trigonometry with geometry.Since the points (0,0) (x,0) (x,y) (0,x) describe a right triangle, with (0,x) (0,0) (x,0) being the right angle, then x2 + y2 = 12, or sin2(theta) + cos2(theta) = 1.If this is not clear, draw a circle around the origin, draw a line from the center to an arbitrary point on the circle, and draw the x and y perpendiculars of that point to each axis. You will see a right triangle. X is sine, Y is cosine, and 1 is hypotenuse. It does not matter if X and/or Y is negative - the squaring will make it positive - and the pythagorean theorem should be visible.


Solve sin3x plus cos3x equals 6?

If you want sin(3x) + cos(3x) = 6, then this is impossible. Sine and cosine will only return values between -1 and 1, so the expression sin(3x) + cos(3x) could only take values from -2 to 2, although even this is to great as sine and cosine of the same number will never both be 1 or -1. Similarly, if you want a solution to sin3x + cos3x = 6, then this is also impossible, because any power of a number between -1 and 1 will itself be between -1 and 1.