-Sin^(2)(Theta) + Cos^(2)Theta =>
Cos^(2)Theta - Sin^(2)Theta
Factor
(Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta))
#Is the Pythagorean factors .
Or
-Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1
Substitute
Cos^(2)Thetqa - 1 + Cos^(2) Theta =
2Cos^(2)Theta - 1
1 + cot2x = csc2x
a2+b2=c2 a squared plus b squared equals c squared
Sin2(theta) + cos2(theta) = 1 for the same reason that the sides of a right triangle squared equal the hypotenuse squared - The pythagorean theorem.In the unit circle (origin = (0,0), radius = 1), an angle theta is the angle made by some arbitrary ray drawn from the origin at an angle relative to the x axis. The point of that ray that intersects with the circle is the point (x,y).Sin(theta) is defined as x, and cos(theta) is defined as y. These are primary trigonometric identities, which link trigonometry with geometry.Since the points (0,0) (x,0) (x,y) (0,x) describe a right triangle, with (0,x) (0,0) (x,0) being the right angle, then x2 + y2 = 12, or sin2(theta) + cos2(theta) = 1.If this is not clear, draw a circle around the origin, draw a line from the center to an arbitrary point on the circle, and draw the x and y perpendiculars of that point to each axis. You will see a right triangle. X is sine, Y is cosine, and 1 is hypotenuse. It does not matter if X and/or Y is negative - the squaring will make it positive - and the pythagorean theorem should be visible.
Pythagorean Eq'n Hypotenuse^(2) = side(1)^(2) + side(2)^(2) This can be reduced to h^(2) = a^(2) + b^(2) In words ; for any right angled triangle the hypotenuse squared is equal to the sum of the squares of other two sides. NB ; The hypotenuse is the longest side and opposite to the right angle. The other two sides are shorter than the hypotenuse and form the right angle.
If you want sin(3x) + cos(3x) = 6, then this is impossible. Sine and cosine will only return values between -1 and 1, so the expression sin(3x) + cos(3x) could only take values from -2 to 2, although even this is to great as sine and cosine of the same number will never both be 1 or -1. Similarly, if you want a solution to sin3x + cos3x = 6, then this is also impossible, because any power of a number between -1 and 1 will itself be between -1 and 1.
No, they do not.
Cosine squared theta = 1 + Sine squared theta
A negative times a negative is always positive. To see why this is, see the link below.
8x squared
negative 2
12 squared plus 18 squared is equal to 468.
25 squared plus 49 squared is equal to 3,026.
6 squared plus 9 squared is equal to 117.
1 squared plus 8 squared or 4 squared plus 7 squared
One plus cosecant squared x is equal to cotangent squared x.
a2 + a2 = 2a2
If x is equal to 5, then x squared plus 25 is equal to 50.