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I'm not sure exactly what this question is asking, but I will attempt to answer.
An angle on the unit circle is created by drawing a straight line from the origin to a point on the circle.
The x-coordinate of a point corresponds to the cosine of the angle.
For example: cos(90o) = 0
The y-coordinate of a point corresponds to the sine of the angle.
For example: sin(270o) = -1
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Why is cotangent positive in the third quad?
If you are familiar with trigonometric functions defined in terms of the unit circle, the x and y coordinates are negative in the third quadrant. As a result, x/y, the ratio that defines cotangent, is positive.
Why is the cosine of 90 equal to 0?
That is the definition. If you take your unit circle (a circle with radius 1 centered at the origin (0,0). you start at (1,0) and go counterclockwise around the circle 90° you end up at (0,1) that 0 is the cosine of the angle 90° In fact, you don't even need the unit circle. Take a circle of any radius r, and draw a ray at 90 degrees. This will intersect the y-axis. So as above, the coordinates are (0,r) (instead of (0,1)) so cos(90 degrees)=x/r=0/r=0
What is cotangent of 270 degrees?
Firstly, with the unit circle (r=1) we need to know that:at 270 degrees our coordinates are (0, -1)sine(270 degrees) = -1cosine(250 degrees) = 0cotangent = cosine / sinetherefore: cot ( 270 degrees) = 0/-1 = 0The answer is 0.
Why does cos negative theta equals positive theta?
You must think of the unit circle. negative theta is in either radians or degrees and represents a specific area on the unit circle. Remember the unit circle is also like a coordinate plane and cos is the x while sin is the y coordinate. Here is an example: cos(-45): The cos of negative 45 degrees is pi/4 and cos(45) is also pi/4
How do you find center of a circle given 3 points on the circle?
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
Find all the coordinates of the points on unit circle?
If x2 + y2 = 1, then the point (x,y) is a point on the unit circle.
What are the tangents of all coordinates in a unit circle?
WHAT ARE THE TANGENTS OF ALL COORDINATES IN THE UNIT CIRCLE?
What numbers have the absolute value of 1?
All complex number that can be represented by the coordinates of points on the unit circle, that is, the circle with its centre at the origin and a radius of 1 unit.
Coordinates of the points in Unit circle?
The points (x, y) of the unit circle are those that satisfy: x2 + y2 = 1 or in parametric form: x = cos t y = sin t as t varies from 0 to 2{pi} radians (= 360o)
Is circle is a two dimensional figure?
Yes, the circle is a 2D object. All of its points only have X and Y coordinates.
What are the coordinates of the point of intersection of the angle -225 and the unit circle?
[-sqrt(2), -sqrt(2)]
Do you name a circle by the points on the circle Like a line segment is named by it's two end points how is a circle named By it's center Point?
You can completely specify a circle in a plane by giving the coordinates of its center point, and the length of the radius.
What is a center coordinate of 2 points known circle?
Knowing two points on a circle does not define a unique circle, so it is impossible to find the centre of the circle as there are infinitely many centres possible.
When the point xy is translated a unit to the leftthe coordinates of the new points can be determined by?
(x-1, y)
Coordinates of points on the unit circle?
Assuming you mean a unit circle with center at the origin, there are an infinite number of coordinate pairs on its circumference. The equation for the unit circle is: x2 + y2 = 1 and anycombination of (x,y) values that makes true will be your answer. The only integer answers are (1,0); (0,1); (-1,0) and (0,-1). Other solutions involve 'special angles' in trig but have irrational numbers and or fractions. 300 --> (1/2 , [sq root 3] / 2) 450 --> ([sq root 2] / 2 , [sq root 2] / 2) 600 --> ([sq root 3] / 2 , 1/2) any combinations of the above with opposite signs will also create coordinates for the unit circle.
How can you find the radius of a circle with coordinates?
Work out the length of the coordinates and half it.
What are the coordinates of the midpoint of GH with end points?
-- The 'x' coordinate of the midpoint is the average of the 'x'-coordinates of the end-points. -- The 'y' coordinate of the midpoint is the average of the 'y'-coordinates of the end-points.
