The cotangent function is the reciprocal of the tangent function, so cot(115 degrees) is equivalent to 1/tan(115 degrees). Since tan(115 degrees) is equivalent to -tan(65 degrees) due to the periodicity of the tangent function, cot(115 degrees) simplifies to -tan(65 degrees), which corresponds to option A.
Tan 42 degrees = 0.9004
Tan(74 degrees) = 3.487414444.....
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
The cotangent function is the reciprocal of the tangent function, so cot(115 degrees) is equivalent to 1/tan(115 degrees). Since tan(115 degrees) is equivalent to -tan(65 degrees) due to the periodicity of the tangent function, cot(115 degrees) simplifies to -tan(65 degrees), which corresponds to option A.
It depends on the angle of depression of the sun. The answer would be 80ft * tan(90-angle of depression) At a depression angle of 40 degrees, the shadow would be 80 * tan (50) which equals 95.340ft
cot 115 deg = - tan25 deg
Tan 42 degrees = 0.9004
Tan(74 degrees) = 3.487414444.....
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
The answer is 0.2867.
it is tan 89.343 degrees
80 degrees latitude means 80 degrees north or south of the equator
x = tan-1(5) = 78.69 degrees