Pythagoras.
The right turn is assumed to be 90 degrees, and moving southwards.
This forms the two shorter sides on a right angled triangle.
They applying Pythagoras.
h^)2) = 5^(2) + 12^(2)
h^(2) = 25 + 144
h^(2) = 169
Don't forget to 'square root' both sides!!!!
Hence
h = sqrt(169) = 13 .
This is a classic Pythagorean triangle.
A trapezium has 4 right angles...Correction: it has 4 angles but they are not right angles. A structure/shape with 4 right angles is a rectangle or square.
The area of a right angle is nothing bro, if you mean the area of a right angle triangle then uts simple formula is : 1/2×Base×Height(Perpendicular of the right angled triangle) Alternative method: Heron's formula!
he's right handed as his other hand is used to control his main weapon.
A right angle is always 90 degrees. Another Answer:- If you mean the length of the hypotenuse then use Pythagoras' theorem which is applicable to right angle triangles
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
a vector quantity has both direction (sign) and magnitude like displacement towards right or left (direction) and has a certain value (magnitude)
You can calculate the magnitude of the displacement by using Pythagoras's Theorem. a2+b2=c2 Let a be 8, b be 6 and c be the magnitude. 8km2+6km2 = c2 64k+36km = c2 100km = c2 10km = c
Angular displacement is a vector quantity because it has both magnitude and direction. The direction of angular displacement is determined by the axis of rotation and follows the right-hand rule, while the magnitude is given by the angle of rotation. As a vector, angular displacement can be added, subtracted, and resolved into components, making it useful in calculations that involve rotational motion.
The magnitude of displacement between Delhi and Bhubaneswar can be calculated using the Pythagorean theorem. The displacement is the hypotenuse of a right triangle where the actual road distance is one side (1745 km) and the distance driven is the other side (1850 km). By applying the Pythagorean theorem (c^2 = a^2 + b^2), the magnitude of displacement is approximately 244.95 km.
Displacement can be negative when an object moves in the opposite direction from its reference point. For example, if an object is initially at position 0 and moves to position -5, the displacement would be -5 units. Negative displacement indicates movement in the opposite direction from the reference point.
Dextral fault movements involve horizontal displacement where the right side of the fault moves horizontally relative to the left side. Sinistral fault movements involve horizontal displacement where the left side of the fault moves horizontally relative to the right side. These movements are determined based on the direction of horizontal displacement across the fault plane.
No. Distance can be greater than displacement, but not less. The magnitude of the displacement between two points is also the minimum possible distance of a path between the same points.However, the displacement can be zero if the distance is not if the object's starting point and ending point are the same.
The acceleration of the bob is directly proportional to the displacement and towards the vertical position.If x represents the angular displacement towards the right, from the vertical. and if x', x'' represent the derivatives, then x'' = -kx where k > 0. This is the characteristic differential equation for SHM.
would for a right triangle to have the same magnitude
To find the displacement, we can use the Pythagorean theorem. The westward distance is 12 km, and the southward distance is 5 km, making a right triangle. The magnitude of the displacement is the hypotenuse of this triangle, which can be calculated as sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13 km.
An offbreak will deviate off the pitch towards the offside (assuming a right handed batsman) whereas outswing means it moves towards off through the air.
In geometry, magnitude is the length of the hypotenuse of a right triangle.