Wiki User
ā 14y agoAcceleration = (change in speed) / (time for the change)
3 = (30) / (time)
3 x (time) = 30
time = 30/3 = 10 seconds
Wiki User
ā 14y agoIF your question accelerates towards me at 6megabytes per second then how long will it take me to answer(deccelerate) it if my current velocity is 299.996 miles per second.
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
An egg would typically reach terminal velocity in about 12 to 15 seconds when dropped from a significant height. Terminal velocity is the point at which the force of gravity on the egg is equal to the force of air resistance, causing the egg to no longer accelerate.
Yes, that's correct. Terminal velocity is the constant speed that a falling object, like a skydiver, eventually reaches when the force of air resistance is equal to the force of gravity pulling the object downward. At this point, the skydiver no longer accelerates and falls at a constant speed.
Speed=15t + 10 The 15t accounts for acceleration, while the initial velocity of 10 is accounted for by +10. As such, the amount of time (t) for the car to reach 20m/s is 2/3s.
How long will depend on the velocity. The closest star would be 4.24 light years away
A space shuttle re-entering Earth's atmosphere typically takes about 30 minutes to reach the Earth's surface once it begins its descent. The exact time can vary depending on the angle of re-entry and the specifics of the descent trajectory chosen.
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.
To find the time taken for an object to reach the peak of its path when thrown straight upward with a velocity of 50 m/s, you can use the formula: time = velocity / acceleration. Since the object is moving against gravity, the acceleration will be the acceleration due to gravity (-9.81 m/s^2). Therefore, the time taken to reach the peak will be 50 m/s / 9.81 m/s^2 = approximately 5.1 seconds.
radius and rpm is not enough you need to know changes in speed over time, so you need to measure how long it takes from "0" velocity to reach maximum velocity
To find the time it takes for the pebble to reach the ground with a final velocity of 58.8 m/s, we need to know the height of the cliff and assume no air resistance. Using the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity (58.8 m/s), (u) is the initial velocity (0 m/s as it's dropped), (a) is acceleration due to gravity (-9.81 m/sĀ²), and (s) is the distance traveled. Rearranging the equation to solve for (s) and using (s = ut + 0.5at^2) to find time, we can calculate the time taken for the pebble to reach the ground.
No, the velocity of a car traveling at a constant speed around a pole remains the same as long as the speed is constant. Velocity is a vector quantity that includes both speed and direction. Since the car is moving in a circular path while maintaining a constant speed, its velocity is constant in magnitude but changes in direction.