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What else can I help you with?
Give you a question about acceleration and decceleration?
IF your question accelerates towards me at 6megabytes per second then how long will it take me to answer(deccelerate) it if my current velocity is 299.996 miles per second.
How long does it take for an egg to reach terminal velocity?
An egg would typically reach terminal velocity in about 12 to 15 seconds when dropped from a significant height. Terminal velocity is the point at which the force of gravity on the egg is equal to the force of air resistance, causing the egg to no longer accelerate.
How long does it take to reach terminal velocity when falling from a height?
Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.
Is it true that the steady speed reached by a skydiver is called the terminal velocity?
Yes. Not just a skydiver; anything that falls long enough will eventually reach "terminal velocity", which means that it will continue falling at a constant speed, because the force of gravity and the force of air resistance are in balance.
How long would it take a drag racer to increase her speed from 10 meters per second to 20 meters per second if her car accelerates at a uniform rate of 15 meters per second square?
Speed=15t + 10 The 15t accounts for acceleration, while the initial velocity of 10 is accounted for by +10. As such, the amount of time (t) for the car to reach 20m/s is 2/3s.
How long would it take you to reach the nearest star from Earth?
How long will depend on the velocity. The closest star would be 4.24 light years away
What happen when you apply a force on an object in space?
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.
To celebrate a victory a pitcher throws her glove straight upward with an initial speed of 6.2 How long does it take for the glove to return to the pitcher?
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
How long does it take for an object thrown straight upward with a velocity of 50 m second to reach the peak of its path?
To find the time taken for an object to reach the peak of its path when thrown straight upward with a velocity of 50 m/s, you can use the formula: time = velocity / acceleration. Since the object is moving against gravity, the acceleration will be the acceleration due to gravity (-9.81 m/s^2). Therefore, the time taken to reach the peak will be 50 m/s / 9.81 m/s^2 = approximately 5.1 seconds.
How long does it take to get a space shuttle into orbit?
It takes about 8.5 minutes for a space shuttle to reach orbit after launch. During this time, the shuttle accelerates to speeds over 17,000 miles per hour to overcome Earth's gravity and reach the necessary altitude. The shuttle then enters a stable orbit around the Earth.
How do you calculate the centrifugal acceleration of a bench centrifuge with an average radius of rotation of 125 mm operating at 4000 RPM?
radius and rpm is not enough you need to know changes in speed over time, so you need to measure how long it takes from "0" velocity to reach maximum velocity
How long does it take a pebble to reach the ground from a cliff with its final velocity of 58.8ms?
To find the time it takes for the pebble to reach the ground with a final velocity of 58.8 m/s, we need to know the height of the cliff and assume no air resistance. Using the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity (58.8 m/s), (u) is the initial velocity (0 m/s as it's dropped), (a) is acceleration due to gravity (-9.81 m/s²), and (s) is the distance traveled. Rearranging the equation to solve for (s) and using (s = ut + 0.5at^2) to find time, we can calculate the time taken for the pebble to reach the ground.
