zero, because there is indeed one zero in that problem.
No, 1 is not equal to 0. 0 is equal to 0 and 1 is equal to 1.
It would be zero because anything times zero is zero.
it is zero as you have no groups to put one into so it can't be shared out equally so therefore anything times by zero is zero.
zero times any number is still zero 0x 1/3 = 0
You probably could figure this one out: it's ZERO.
it is zero
1
In layman's terms: if zero is the primary number and you were to multiply that primary number to any number, it's still zero. Multiplying 1 times 1 equals to 1. One times itself is one. So zero, meaning nothing times 1 is equal to nothing since there is nothing to begin with.
The property illustrated by the equation (3 \times 2 \times 1 \times 0 = 0) is the Zero Property of Multiplication. This property states that the product of any number and zero is always zero, regardless of the other numbers involved in the multiplication. Therefore, in this expression, the presence of zero ensures that the entire product equals zero.
zero divided by one equals zero.
Zero because anything times by 0 is 0, even infinite time 0 is 0
Interesting question. 0 + 0 = 0 x 0, but why? Let's take 1 +1 as an example. 1 + 1 = 2, because one of something plus one of something equal two of something. So, if you have nothing and add it to nothing, you must have nothing. Therefore, 0 + 0 = 0. Now, let's take 1 x 1. 1 x 1 = 1, because one of something one time is only that one something. So, if you have nothing and multiply it zero times, you still have nothing. Therefore 0 x 0 = 0. So, if you have the outcome of 0 in each equation, 0 + 0 must be the same as 0 x 0, because they will always equal 0. Zero is Zero. No further explanation required.