x + 1 = 0
Subtract 1 from each side:
x = -1
0 because X= -1
x = 0
x= -1 answer: 0
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
x = 0
solution: y = 0 x = -1
1
x=2y-1
(11, 1, 0) and (0, 1, 11) are the two possible solutions.
2
(x + 6)(x + 1) = 0 so x = either -1 or -6
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)