what is the domain of g(x) equals square root of x plus 1?
√(x+1) ≥ 0
x+1≥0
x≥-1
Domain:
[-1,∞)
Domian is x>-6 Range is y> or equal to 0
84
The square root of 27 plus the square root of 5 = 7.4322204
x
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
Domian is x>-6 Range is y> or equal to 0
68
Domain is greater than or equal to zero. same with range
a = -4
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
84
Two times the square root of three plus five times the square root of three plus four times the square root of three equals eleven times the square root of three.
The exact square root of 9999999999999999999999 is 33 times the square root of 9182736455463728191.
Square root of 3=1 so 1+4=5