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1.34kPa = 1340Pa
1Pa = 1N/m^2
1N = 1kg.m/s^2 (m/s^2 or acceleration, which on the earths surface is normally approximated as g = 9.81m/s^2)
therefore
1Pa = 9.81kg/m^2
thus the equivilant "weight" of that pressure in kilograms can be determined by dividing 9.81 by the area it's acting on in m^2 and then multiplying it by the pressure, in this case 1340Pa
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∙ 15y ago
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