20 10 in B T the L are G B
10 L - A 3 L -B 1) B --> A fill B 2) B --> A fill B 3) B --> A A will have 9 L again fill B 4) B --> A A will have 10 and B will have 2 empty A 5) B --> A B will have 0 and A will have 2 fill B 6) B --> A A will have 5L problem solved in 6 steps
b=l-3 P=2l+b 36=2l+b Sub b=l-3 into 36=2l+b 36=2l+b 36=2l+(l-3) 36=2l+l-3 39=3l l=13 cm Sub l=13 into b=l-3. b=l-3 b=13-3 b=10 cm Therefore, the length of each of the two equal sides is 13 cm and the base is qual to 10 cm.
== == 2(L + B) = 44, so L + B = 22; also LB = 120. So we come up with L(22 - L) = 120, leading to L = 12 and B = 10.
Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2
Find the difference between the two teams' win and losses, divide by two. Example: Team A..........W-10 L-3 Team B..........W- 8 L-5 Team B is 2 games behind Team A Team A..........W-10 L-3 Team B..........W- 8 L-4 Team B is 1 1/2 games behind Team A
4 l on a c = 4 legs on a chair, 4 f on b b is 4 faces on big ben------- so what is 10 p in g
Area = 2*(L*B + B*H + H*L) = 2*(10 + 20 + 50) = 2*80 = 160 cm3
Suppose the length is L and the breadth is B. Then since perimeter = 58, 2*(L+B) = 58 so that L+B = 29 that is L = 29-B Now Area = L*B = 204 That is (29-B)*B = 204 Or B2 - 29B + 204 = 0 which is equivalent to (B-12)*(B-17) = 0 So, using L+B = 29, L and B are 12 and 17.
ten pins on a Bowling lane
G A B G l G A B G l B C D l B C D l D E D B A D l D E D B A D l G G D G D G ..
it's possible press a,up,b,left,right,a,a,a,a,b,b,b,b,b,b everything is on the controls now press r,r,r,r,r,l,l,l,l,l,a,b,up,down,l,r,right,left to get unlimited master balls