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What is the area of a rectangle with a perimeter of 40 m and a length of 8m?
Wiki User
∙ 11y ago
Perimeter = 40
So 2*(L + B) = 40 therefore L + B = 20
Then L = 8 gives B = 12
Therefore the Area is L*B = 8*12 = 96 m2
Perimeter = 40
So 2*(L + B) = 40 therefore L + B = 20
Then L = 8 gives B = 12
Therefore the Area is L*B = 8*12 = 96 m2
Perimeter = 40
So 2*(L + B) = 40 therefore L + B = 20
Then L = 8 gives B = 12
Therefore the Area is L*B = 8*12 = 96 m2
Perimeter = 40
So 2*(L + B) = 40 therefore L + B = 20
Then L = 8 gives B = 12
Therefore the Area is L*B = 8*12 = 96 m2
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoPerimeter = 40
So 2*(L + B) = 40 therefore L + B = 20
Then L = 8 gives B = 12
Therefore the Area is L*B = 8*12 = 96 m2
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