10^4
Do you mean "equations involving exponential functions"? Yes,
that is supposes to be 18 to the 6x power
It's a simple question. It can be solved by EXPONENTIAL NOTATION111111*99991*105*9*103=1*9*105+3=9*108THIS IS THE ANSWER!
8 = 23 So 8*8*8*8 = 84 = (23)4 = 23*4 = 212
4 = 22 So 4*4*4*4 = 44 = (22)4 = 22*4 = 28
2
Do you mean "equations involving exponential functions"? Yes,
depends on the question but an EXPONENTIAL EQUATION is in the for 2^x = 4 and you have to solve for x.
additive
For an exponential function: General equation of exponential decay is A(t)=A0e^-at The definition of a half-life is A(t)/A0=0.5, therefore: 0.5 = e^-at ln(0.5)=-at t= -ln(0.5)/a For exponential growth: A(t)=A0e^at Find out an expression to relate A(t) and A0 and you solve as above
If you mean 4-2, that is, by definition, the same as 1 / 42.
An algorithm that completes in "polynomial time" is faster to solve than an algorithm that completes in "exponential time" in most of the important cases where it needs to be solved. An algorithm that completes in "polynomial time" the time to solve is always determinable by a polynomial equation (e.g. x^2, x^4+7*x^3+12*x^2+x+19, x^8392). An algorithm that completes in "exponential time" the time to solve can only be determined an exponential equation (e.g. 2^x, e^x, 10^x, 982301^x). Exponential equations give larger value answers than polynomial equations after a certain input value and then increase progressively faster. This makes "exponential time" algorithms take much longer than "polynomial time" algorithms to solve, often making many of them effectively unsolvable for certain cases. Many of the most important algorithms needed to solve real world problems are "exponential time" algorithms.
that is supposes to be 18 to the 6x power
3^6 = 729
8 = 23 So 8*8*8*8 = 84 = (23)4 = 23*4 = 212
It's a simple question. It can be solved by EXPONENTIAL NOTATION111111*99991*105*9*103=1*9*105+3=9*108THIS IS THE ANSWER!
4 = 22 So 4*4*4*4 = 44 = (22)4 = 22*4 = 28