$10x2/3
10x2 - 29x = 21 10x2 - 29x - 21 = 0 so x = -0.6 or x = 3.5
10x2-5x-5 = (10x+5)(x-1)
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)
the answer: 20
10x2 + 101x + 10 = (10x + 1)(x + 10)
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
That's not as problem, unless you're practicing the procedure to simplify fractions.(10x2 - 2x)/(4x) = (10x2)/(4x) - (2x)/(4x) = 2.5x - 0.5
The answer is 21
(10x + 3)(x - 1)
4x3+10x2+2x+5= (2x+5)(2x2+1)
Quotient rule. d/dx[f(x)/g(x)] = g(x)f'(x) - f(x)g'(x)/[g(x)]2 d/dx[X3/10X2] 10X2*3X2 - X3*20X/(10X2)2 30X4 - 20X4/(10X2)2 10X4/10X4 = 1 ===