It depends on what the initial velocity was. If it was 0, then:
11-0 = 2.2 m/s squared
5
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
80 m/s2 up
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
80 m/s 2 up
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
Acceleration(a) = [final velocity(v) - initial velocity(u)] / time(s) Algebrtaically a = [ v - u ] / s A negative result indicates deceleration a = [20 - 40 ]= / 4 a = [-20] / 4 a = -5 m/s^(2) This is negative which matches the question of slowing down/deceleration.
80 m/s2 up
The average acceleration during any interval is (change in speed) divided by (time for the change).A = (25 - 10)/5 = 15/5 = 3 meters per second2
80 m/s 2 up
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
Acceleration = (Change in speed)/(Time) a = (v-u)/t = (500-1000)/5 = -500/5 = -100 Acceleration is -100 ms-2
5 seconds
apex :) 2.2 m/s2
If he started out from "rest" (zero speed), then his average acceleration for the 5 seconds is50/5 = 10 meters per second2
Her average acceleration is 2.2 meters per second per second (2.2 m/s2 ).
2.2