the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
80 m/s2 up
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
66.7 m/s2
80 m/s2 up
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
To calculate this, you divide the change in velocity, by the time.
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
Only if they have a heart attack, but not likely.
66.7 m/s2
66.7 m/s2
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
When a skydiver opens their parachute, air resistance increases which slows down the skydiver. Terminal velocity is the maximum speed a falling object can reach when the force of gravity is balanced by the force of air resistance. Opening the parachute decreases the skydiver's speed, allowing them to land safely.