The prime factorization of 4096 is 2^12.
It is: 2 to the power of 12 = 4096
4096
212 = 4096
14
4096
12 to the power of 9 equals 5,159,780,352
to find the memory from address lines. you just have to make address liness power of 2, as shown below for 12 address lines 212 bits. 212 = 22 * 210 = 4 Kbthat means we can address 4 Kb from 12 address lines.........
1hour=60minutes 5minutes=one division 60 divided by 5=12 1>>>>2>>>>4>>>>8>>>>16>>>>32>>>>64>>>>128>>>>256>>>>512>>>1024>>>>2048>>>>4096
2^12=4096
It is 212 = 4096, whose factors are 2n where n = 0, 1, 2, ... , 12.
2,985,984