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We first determine the ratio of relative computer speed to the total collective work done. Since two computers are involved, that requires 240 minutes of total execution time. The first computer performs twice as slowly as the second, so it runs at "2x" amount of time used. The second computer runs at "x" amount of time. The initial equation is:

1x + 2x = 240

The result of combining like terms and simplifying the result comes to:

x = 80

Therefore, computer 1 performs 80/240 (or 1/3) of the work, while the faster computer performs 160/240 (or 2/3) of the work. To come up with the final amount of time it would take, we set up two equations:

1/3x = 240

2/3x = 240

This means that it would take the slower computer 720 minutes to complete the task by itself, while the faster computer would finish in only 360 minutes.

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13y ago
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Anonymous

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3y ago
2 hours is equevalent to 120 mins

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Q: 1 If One computer can do a job twice as fast as another and Working together both computers can do the job in 2 hr How long would it take each computer working alone to do the job?
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