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1 You roll a number cube once Then you roll it again What is the probability that you will get a 6 on the first roll and a number greater than 3 on the second roll?
Wiki User
∙ 13y ago
1/6*1/2 = 1/12
Wiki User
∙ 13y ago
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What is the probability for rolling a number cube?
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
What is the definition of experimental probability?
Experimental Probability: The number of times the outcome occurs compared to the total number of trials. example: number of favorable outcomes over total number of trials. Amelynn is flipping a coin. She finished the task one time, then did it again. Here are her results: heads: three times and tails: seven times. What is the experimental probability of the coin landing on heads? Answer: 3/10 Explanation: Amelynn flipped the coin a total of 10 times, getting heads 3 times. Therefore, the answer is: 3/10.
What is the probability of drawing an eight and then drawing another eight assuming the first card is put back in he deck before the second draw?
For any particular card, (eg an 8) there are 4 such cards in a pack of 52. So the probability of drawing one of these is 4/52, or 1 in 13. After restoring the card to the pack and doing it again the probability is a further 1/13. So the overall probability of doing the 2 things in succession is 1/13 x 1/13 = 1/169.
What is the theoretical probability of rolling two dice 100 times?
The theoretical probability is 1. Lots of people have done it in the course of their lives so it is an event that has happened and will happen again.
How would you calculate the probability of an event occurring?
There are two main methods: theoretical and empirical. The first of these is used when there is a relatively simple model for the possible outcomes of a trial. For example, if you roll a fair die, laws of physics suggest that each of the six faces is equally likely to end up on the top face. The probability for each of the six numbers is, therefore, 1/6. The second method is used when there is no satisfactory model based purely on theory: if you have a loaded die, for example. It may, just about, be possibly to analyse the physical properties of the mass distribution within the coin and develop an appropriate model for the outcome of a throw. However, it is simpler to use the second method. Given the chance, roll the die again and again (and again and again and ... ) and record the outcomes. The probability of any particular outcome is the proportion of the trials that result in that particular event. Thus, if a loaded die comes up 6 fifty times out of 200 throws, then the probability of throwing a 6 is 50/200 = 0.25.
What is the probability for rolling a number cube?
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
What does estimated experimental probability mean please someone answer?
One way of finding the probability is to carry out an experiment repeatedly. Then the estimated experimental probability is the proportion of the total number of repeated trials in which the desired outcome occurs.Suppose, for example you have a loaded die and want to find the probability of rolling a six. You roll it again and again keeping a count of the total number of rolls (n) and the number of rolls which resulted in a six, x. The estimated experimental probability of rolling a six is x/n.
How do you decide which two numbers is greater?
A positive number is greater than a negative number. If a positive number is greater than another, the corresponding negative numbers are smaller. For example, since 4 > 3, -4 < -3. For two positive numbers: The number with more digits is greater. If they have the same number of digits, the number with the greater first digit is greater. If they are equal, look at the second digit, which will decide which number is greater, and so forth, up to the last digit. For example, 12500 is greater than 12480: they have the same number of digits, the first two digits are the same, but the third digit is the tie-breaker. For numbers with decimals, first apply the rules above for the whole part. If they are equal, check the first digit after the decimal point, then the second, etc., until you find a "tie-breaker". For example, 0.2522 is more than 0.2517. Once again, the first two digits are the same, the third is the tiebreaker.
If you select two cards from a deck of 52 cards what is the probability that the first card is an 6 of diamaond and the second card is an 3 of hearts?
First off, how do I calculate the probability that any one event occurs. The answer is equal to: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 6 of Diamonds in any deck of cards). The total number of chances equal 52 (there are 52 cards to choose from). Therefore the probability of picking a 6 of Diamonds on the first card is 1/52 or .019. In order to calculate the probability that the first card is a 6 of Diamonds AND the second card is a 3 of Hearts, you multiply the two probabilities. Prob. of 1st Card 6D AND 2nd Card 3H = Prob. 1st Card 6D * Prob. 2nd Card 3H We already know the probability of getting a 6 of Diamonds on the first card is 1/52 or .019. To calculate the probability of getting a 3 of Hearts on the second card, it is important to remember that random occurances do not affect the probability of other random occurrances. What I mean is, if I were to draw a 6 of Diamonds from a deck of cards and then replace it, the probability that I would pick a 6 of Diamonds again is the same as it was the first time. Even if I flip a coin 5 times in a row and they all landed on heads, the probability that I would flip another heads is still 50/50. So basically we can ignore what happened on the first draw, and jsut calculate the probability of getting a 3 of Hearts. Again we use our probability formula: Number of Possible Chances of Success / Total Number of Chances In this case, the number of possible chances of success is one (there is only one 3 of Hearts in any deck of cards). The total number of chances equal 52 (THIS ASSUMES THAT WE PUT THE 6 OF DIAMONDS BACK INTO THE DECK AFTER THE FIRST DRAW IF NOT THE NUMBER OF CHANCES IS 51). Therefore the probability of picking a 3 of Hearts on the second card is 1/52 or .019. Multiply the two probabilities together to get the probability of both occurring: 1/52 * 1/52 = 1/2704 = .00037 (or a .037 percent of a chance)
With 38 possible compartments what's the probability that you get the same number twice?
The answer depends on how many are chosen, whether once chosen you can chose them again.
What is the probability of drawing two hearts from a standard pack of cards is 3 divided 51 what is the probability that the two cards drawn are not both hearts?
The probability of drawing a heart from a fair deck is 1 in 4. If the card is replaced then the probability is again 1 in 4. The probability of drawing a card other than a heart is 3 in 4. Once again if the card is replaced then the probability remains 3 in 4
Which number appear most often for minnesota hot lotto?
Apparent tendencies from the past don't indicate future tendencies in such a case. If during the last year some number appeared more frequently, that was a coincidence, and it won't affect the probability of the number appearing again in the next lotto drawing. The numbers are random, each number should have the same probability.
Will you have Hyperemesis gravidarum in your second pregnancies?
If you have Hyperemesis Gravidarum during one pregnancy you won't necessarily have it in another but you are at greater risk for having it again.
What is the probability of getting the same number on a roll of 3 dice?
(probably but very unlikely) ----------------------------------- A better answer would be as follows. Throw the first dice. It does not matter which number turns up. Let's suppose it was a 2; Now there is only one 2 out of six different numbers when you throw the second dice. So the probability of scoring another 2 is 1 out of 6 = 1/6 Now for each of the results from the two dice which we have read there is only one 2 from the 6 possible numbers, which again means a probability of 1 out of six = 1/6 So the final probability is found by multiplying 1 (certainty) for the first dice by 1/6 for the second dice by 1/6 for the third dice, which = 1/36
If you draw a club at random from a deck of cards and then draw again after replacing the first card the probability of drawing another club is smaller the second time compared to the first time?
No, it is the same.
A six sided cube numbered 1 through 6 is rolled 120 timesThe number 4 comes up 19 times what is the theoretical probability of rolling a 4?
Because we are only modeling one event, all six outcomes of the die are equally possible. The probability of rolling a four (or, for that matter, any number) is 1/6, or .166666 repeating. Now, since we are modeling 120 rolls, the theoretical number of outcomes of four (or, again, any number) is 1/6 * 120 = 20 outcomes. The second sentence of the problem is unnecessary.
Why is a nutcracker is second class?
A lever that has the load between the fulcrum and the effort is known as a second order lever. Once again, the further away the effort is from the fulcrum and the load the greater the mechanical advantage of the lever.
