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20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
If 7m = 4n+2 and 7m+2 = 8 m = 6/7 and n = 1
5n-2+2=4n 5n=4n n=0
(4n - 1)(3n + 2)
4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
7n + 2 = 4n + 17Subtract 2 from each side:7n = 4n + 15Subtract 4n from each side:3n = 15Divide each side by 3:n = 5
3 + 3n = 9 + 2n + 4n n = -2
4n
8 = 4n n = 2
The first three terms of the nth term 4n-2 would be obtained by plugging in n=1, n=2, and n=3 into the expression. Therefore, the first term would be 4(1) - 2 = 2, the second term would be 4(2) - 2 = 6, and the third term would be 4(3) - 2 = 10. So, the first three terms are 2, 6, and 10 for the given nth term 4n-2.