The first three terms of the nth term 4n-2 would be obtained by plugging in n=1, n=2, and n=3 into the expression. Therefore, the first term would be 4(1) - 2 = 2, the second term would be 4(2) - 2 = 6, and the third term would be 4(3) - 2 = 10. So, the first three terms are 2, 6, and 10 for the given nth term 4n-2.
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t(n) = 4n2 - 4n + 2
5 first terms in n²+3
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
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5, 11, 17, 23, 29