They are all prime numbers
573, aka 1*573. 1146, aka 2*573. 1719, aka 3*573. Are you sensing a pattern here?
No.
yes
286 with remainder 1.
573 rank = (oddnumber + 1) / 2
5.73 x 10^2
The factors of 1146 are: 1, 2, 3, 6, 191, 382, 573, 1146
10
The GCF of 23 and 46 is 23. 23/23 = 1 46/23 = 2 23/46 = 1/2
(23/2)2 x2 - 23x = 0 x2 - 23x + (23/2)2 = (23/2)2 (x - 23/2)2 = (23/2)2 x - 23/2 = 23/2 x = 23/2 + 23/2 x = 23 Of course you could come to this solution much more easily by dividing the whole equation by x at the start. There really is no need to complete the square in this case: x2 - 23x = 0 x - 23 = 0 x = 23
2 * 23 = 46
The prime factorization of 46 is: 2 x 23