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What r the dimensions of mutual inductance?
Obviously there is more than one way to do this. VL = Ldi/dt Volts has units of Joules/Coulomb: J/C i has units of Coulombs/second: C/s So di/di is C/s^2 L has units of J/C / C/s^2 = Js^2/C^2 Ic = CdV/dt => Ic/dV/dt = C/s / J/C-s = C/s * C-s/J = C^2/J C has units of C^2/J OR you could just type Q = CV => C = Q/V = C/J/C = C^2/J same answer R = V/I => J/C / C/s = J-s/C^2
What is the area formula for an triangle?
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
What is the area of a 2 by 8 by 8 and a half cm triangle?
Assuming 2, 8, and 8.5 are the lengths of the sides, the area is 7.929 cm^2. Using Heron's formula, A = sqrt(s * (s-a) * (s-b) * (s-c)) where a, b, and c are the lengths of the sides and s = (a + b + c)/2
Area of scalene triangle?
The answer depends on what information you do have.Suppose you know only the lengths of the sides (a, b and c), then let s = (a + b + c)/2.Then area = sqrt[s*(s - a)*(s - b)*(s - c)]If 2 sides and the included angle, then area = 1/2*a*b*sin(C).There are other formulae.
How is the area of a triangle affected if the height is doubled but the length of the base remains the same?
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
2 equals S of a C?
2 Sides of a Coin
2 S T E C?
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What is the surface area triangular prism?
If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "
What is the area of oblique triangles?
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
How do you find the area of an oblique triangle which 3 sides are given?
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
What is the area of a triangle when given are the length and the sides?
Suppose the sides are a, b and c units. Calculate s= (a+b+c)/2 Then Area = sqrt[s*(s-a)*(s-b)*(s-c)] square units
What is the mathematical formula for finding area?
There are different formulae for different shapes. The formulae also depend on the information available and the mathematical skills of the user. I can think of at least three for a triangle alone:1/2*base*height1/2*a*b*sin(C) where a and b are two sides and C is the included angle.sqrt[s*(s-a)*(s-b)*(s-c)] where a, b and c are the three sides and s = (a+b+c)/2
