It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
The answer depends on what information you do have.Suppose you know only the lengths of the sides (a, b and c), then let s = (a + b + c)/2.Then area = sqrt[s*(s - a)*(s - b)*(s - c)]If 2 sides and the included angle, then area = 1/2*a*b*sin(C).There are other formulae.
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
2 Sides of a Coin
C. S. Forester died on April 2, 1966 at the age of 66.
Two sides to a coin.
If A is the area of a triangle with side length a, b and c and s is (a+b+c)/2 ( known as the semiperimeter of the triangle) Then, Heron's formula tells us that A=square root of [s(s-a)(s-b)(s-c)].
L=sqr((1/2 a+b+c) * (s-a) * (s-b) * (s-c))
Cinderella has 2 Ugly Sisters
2 = Sides that a Card / Conflict / Coin has
I-C-I-R-U-S- - 2011 A Civil Discussion 2-2 was released on: USA: 18 January 2012
One possible form is sqrt{s*(s-a)*(s-b)*(s-c)} square units where the lengths of the three sides of the triangle are a, b and c units and s = (a+b+c)/2.