Q: 2 equals S of a C?

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Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.

(direct variation) t = kr, where k is any constant, and it is called the constant of the variation.t = 2 when r = 26t = kr2 = k(26) (divide by 26 to both sides)2/26 = kk = 1/13(indirect variation) t = c/s, where c is any constant, and it is called the constant of the variation.t = 2 when s = 26t = c/s2 = c/78 (multiply by 78 to both sides)156 = c

If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18

16.5

a + c - b = 3 + 2 - 5 = 5 - 5 = 0

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Let s = semiperimeter (ie half the perimeter) So s = (a+b+c)/2 = (5 + 8 + 11)/2 = 24/2 = 12 Then area = sqrt[s*(s-a)*(s-b)*(s-c)] = sqrt[12*7*4*1] = sqrt[336] = 18.33 square units.

Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12

Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.

7=c(s) obviously

(direct variation) t = kr, where k is any constant, and it is called the constant of the variation.t = 2 when r = 26t = kr2 = k(26) (divide by 26 to both sides)2/26 = kk = 1/13(indirect variation) t = c/s, where c is any constant, and it is called the constant of the variation.t = 2 when s = 26t = c/s2 = c/78 (multiply by 78 to both sides)156 = c

2 popes called john paul 1708 christopher wren finishes st pauls cathedral

If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18

16.5

a + c - b = 3 + 2 - 5 = 5 - 5 = 0

b = sqrt32 or 4 root 2