(2x + 7)(x - 2)
(2x + 7)(x - 2)
2x2 + 3x - 20 = (x + 4)(2x - 5).
No.
This expression could be reordered as 1 + 3x + 2x2.
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
(x-2)(2x+7)
(2x + 7)(x - 2)
(2x + 7)(x - 2)
2x2 + 3x + 1 = (x + 1)(2x + 1)
2x2 equals 5
-11
2x2 + 3x - 20 = (x + 4)(2x - 5).
No.
2x2-4x-3x+6 2x2-7x+6 (2x+3)(x+2)
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
This expression could be reordered as 1 + 3x + 2x2.
No. You'd have to use the ABC-formula