4x
(2x + 7)(x - 2)
f(x) = 3x4 - 2x2 + 7f ' (x) = 12x3 - 4xf ' ' (x) = 36x2 - 4
(2x + 7)(x - 2)
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
2x2 equals 5
4x
(2x + 7)(x - 2)
f(x) = 3x4 - 2x2 + 7f ' (x) = 12x3 - 4xf ' ' (x) = 36x2 - 4
(x-2)(2x+7)
65
(2x + 7)(x - 2)
(2x + 7)(x - 2)
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
=3x+7
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
(-3x - 1)(3x - 7)