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What else can I help you with?
What are the roots of the quadratic equation y equals 2x2 plus 3x-20?
2x2 + 3x - 20 = (x + 4)(2x - 5).
Value of the discriminant for 2x2 - 3x plus 1 equals 0?
The discriminant is 1.
What the x value of 2x square plus 3x plus 9 equals 0?
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
Rewrite the equation in function form -3x plus y equals 12?
y=3x+12
What is the differential of this function Find the differential of f y equals f start parentheis x end parentheis equals 2x raised to 2 minus 3x plus 10 dy equals?
y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx
2x2 - 3x plus 7?
2x2 equals 5
What best describes the function below fx equals 2x2-3x plus 1?
B- It is a many-to-one function
What are the roots of the quadratic equation y equals 2x2 plus 3x-20?
2x2 + 3x - 20 = (x + 4)(2x - 5).
How do you complete the square 2x2 - 3x plus 1 equals 0?
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
Value of the discriminant for 2x2 - 3x plus 1 equals 0?
The discriminant is 1.
What is 2x2 plus 3x plus 1 factored?
2x2 + 3x + 1 = (x + 1)(2x + 1)
What is the derivative of 2x2 plus 3x plus 7?
y = 2x^(2) + 3x + 7 dy/dx = 2(2)x^(2-1) + 3(1)x^(1-1) + 7(0)x^(0-1) dy/dx 4x^(1) + 3x^(0) + 0 dy/dx = 4x + 3(1) dy/dx = 4x + 3 The answer!!!!! I have made a bit of 'heavy weather' of this but only to try and show you how it works out.
2x2-3x plus 1 equals 0?
(2x - 1)(x - 1) so x = ½ or 1
2x2 plus 3x plus 1 equals 0?
factorises as (2x + 1)(x + 1) so x = -0.5 or -1
Is y equals -3x plus 3 a function?
yes
What is 2x2 plus 3x-5?
-11
X2 plus 7x equals -2x2 plus 6?
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
