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Q: 2x plus 5 equals 10x equals?

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2x+5=-91-10x 12x+5=-91 12x=-96 x=-8

10x + 5 which is also equal to 5(2x + 1)

x=5. 10x-4x (6x) +10-6x (=10) If 10 is 2x, x=5.

6x2 + 10x = 2x*(3x + 5)

13 + 2x = 32x = 3 - 132x = -10x = -5

10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5

3x-2x-3x+6 = 5-10x+9x-5 Clean up both sides (the fives on the right cancel out) -2x + 6 = -1x add 2x to both sides 6 = x ■

6x2 + 10x = 2x(3x + 5)

4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)

If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2

2x(3x + 5)

6x-8+2x-5 = 7-2x 6x+2x+2x = 7+8+5 10x = 20 x = 20/10 x = 2

10x + 5 = 5(2x + 1)

They are: (4x-5)(2x+5)

12x + 5 - 2x =(12x - 2x) + 5 =10x + 5 =5 (2x + 1)

2x(3x + 5)

2x(3x + 5)

395

x -3x + 4 = 3 - 9-2x + 4 = -6-2x = -102x = 10x = 5

If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)

2xy - 10x + 3y -15 = 2x(y - 5) + 3(y - 5) =(y - 5)(2x + 3)

5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8

2x + 5 = 13 2x = 8 x = 4

2x(2x2 - 9x + 5)

2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5