6x2 + 10x = 2x*(3x + 5)
(6x + 1)(x + 13)
x2 + 6x + 8 =(x + 2)(x +4)
We know that when you submit questions you aren't free to use the right format to make the mathematical terms crystal clear. It is likely that you mean "x squared times 6 plus x squared times 2", which is clearer. You can factor out the "x squared" and you will see that you get "x squared times 8". You COULD mean (6x) squared plus (2x) squared, which would be different. 6x times 6x would equal x squared times 36, so your answer will be much different.
(4x - 3)(2x + 3)
since y = 3x+1 we have y squared =(3x+1) squared x^2 + y^2 = 25 x^2 + (3x+1)^2=25 x^2 + 9x^2+ 6x+1 = 25 10x^2 + 6x + 1 = 25 10x^2 + 6x -24 = 0 solve x from quadratic formula x = 1.28 y = 3x + 1 = 4.83
That depends what the value of x is.
(6x + t)(3x + t)
(6x + 1)(x + 13)
(6x + 1)(x + 2)
-116
x2 + 6x + 8 =(x + 2)(x +4)
We know that when you submit questions you aren't free to use the right format to make the mathematical terms crystal clear. It is likely that you mean "x squared times 6 plus x squared times 2", which is clearer. You can factor out the "x squared" and you will see that you get "x squared times 8". You COULD mean (6x) squared plus (2x) squared, which would be different. 6x times 6x would equal x squared times 36, so your answer will be much different.
5x(6x + 7y + 8)
(x + 3)(x + 3)
4x-3+6x+3 4x+6x=10x -3+3=0 10x is the answer!
(6x - 1)(6x - 1)
To simplify the expression ( \frac{6x^2 + 4x^2 + 2x}{2x} ), first combine the like terms in the numerator: ( 6x^2 + 4x^2 = 10x^2 ), so the expression becomes ( \frac{10x^2 + 2x}{2x} ). Next, factor out a ( 2x ) from the numerator: ( \frac{2x(5x + 1)}{2x} ). The ( 2x ) in the numerator and denominator cancels out, resulting in ( 5x + 1 ).