2x(3x + 5)
6x2 + 10x = 2x*(3x + 5)
2x(3x + 5)
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
6x2=12 2x-28=?
6x2 + 7x - 5 = (3x + 5)(2x - 1)
Simplifying 6x2 + 23x + 7 Reorder the terms: 7 + 23x + 6x2 Factor a trinomial. (7 + 2x)(1 + 3x) Final result: (7 + 2x)(1 + 3x)
6x2-18x+12 = (6x-6)(x-2)
x2+10x-336
5
2(3x^2 + 6x + 2)
(2x - 1)(3x - 2)