25.
In one throw the odds are 2/8. That is, th
ere are 8 possible outcomes, two of which are considered "winning" combinations (HHH and TTT).
In 100 throws, you would expect each of the 8 outcomes to occur 12 or 13 times (the average of the number of times each of the 8 outcomes occurs will always be exactly 12.5, whether the distribution is even or whether you got all heads all 100 throws and all the other combinations were zero). You would expect the number of times you get all heads or all tails - two of those combinations - to be 25.
Half the time they will be the same, half the time they will be different. Half of the time that they're the same they will be heads, half the time they are the same they will be tails. It's your homework, YOU figure it out. The way I figure it. There are four options: 1) heads / heads 2) heads / tails 3) tails / heads 4) tails / tails By process of chance, one out of four times both coins will be heads/heads. Therefore 780/4 = 195 times.
around 45
Each coin has 2 outcomes. Either being heads or tails. Take the outcome of each coin to the root of the number of coins. (1/2)^3 = .125 = 12.5% or a 1 in 8 chance. Take .125 and times it by 100 to get the probability out off 100 times. .125 x 100 = .125 which = 12.5%= 1 in 8 chance
The expected number is 3750.
Out of the 1,000 tosses, you should expect to see 2 heads 250 times (1/4 of them), 2 tails 250 times (1/4 of them), and one of each 500 times (1/2 of them). Out of the 2,000 coin faces that show, you should expect to see very close to 1,000 heads (1/2 of them) and 1,000 tails (1/2 of them).
If we toss three coins 240 times, how many times can we expect the coins to have three tails showing?
Half the time they will be the same, half the time they will be different. Half of the time that they're the same they will be heads, half the time they are the same they will be tails. It's your homework, YOU figure it out. The way I figure it. There are four options: 1) heads / heads 2) heads / tails 3) tails / heads 4) tails / tails By process of chance, one out of four times both coins will be heads/heads. Therefore 780/4 = 195 times.
around 45
1heads heads heads 2heads heads tails 3heads tails heads 4heads tails tails 5tails tails tails 6tails tails heads 7tails heads tails 8tails heads heads
There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.
Less. The more times the coin is tossed, the more likely it will reflect the actual odds of .5 heads and .5 tails.
Each coin has 2 outcomes. Either being heads or tails. Take the outcome of each coin to the root of the number of coins. (1/2)^3 = .125 = 12.5% or a 1 in 8 chance. Take .125 and times it by 100 to get the probability out off 100 times. .125 x 100 = .125 which = 12.5%= 1 in 8 chance
The expected number is 3750.
The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.
Out of the 1,000 tosses, you should expect to see 2 heads 250 times (1/4 of them), 2 tails 250 times (1/4 of them), and one of each 500 times (1/2 of them). Out of the 2,000 coin faces that show, you should expect to see very close to 1,000 heads (1/2 of them) and 1,000 tails (1/2 of them).
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.