Let's call one coin A and the other B. omes
The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes.
The possible outcomes for a single die (as in dice) are six since a die has six faces,
So four times six is twenty four possible outcomes.
It is 1/12.
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
50/50
Two coins tossed sample space is (H=Heads, T = Tails) as follows. HH, HT, TH, TT is the sample space.
possible
24 possible outcomes.
The possible outcomes areHH, HT, TH and TT.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
The total number of outcomes is 2^5 = 32.
Coins do not have numbers, there is only the probability of heads or tails.
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
It is 1/12.
1/4 if they are tossed only once.
Doubloons
Two
There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.
If they are fair coins, it is 1/16.