235
47 x 5 = 235
9.4 times 5 = 47
47 times 5
8 can go into 47 a total of 5 times, since 8 multiplied by 5 equals 40, which is the largest multiple of 8 that is less than 47. When you divide 47 by 8, the result is 5 with a remainder of 7. Therefore, the answer is 5 times with a remainder.
8 fits into 47 a total of 5 times, since 8 multiplied by 5 equals 40. The next multiple, 8 times 6, equals 48, which exceeds 47. Therefore, the maximum number of whole times 8 can fit into 47 is 5.
47 times
No, 7 does not go into 47 a whole number of times.
47 / 6 = 7.8333333 (recurring)So, 6 goes into 47;7.8333333 .... times, or7 times with a remainder of 5
6x7=42 42+5=47 5 over 6x7=47
It goes in 9 and 2/5 times
6 can go into 47 a total of 7 times, since 6 multiplied by 7 equals 42. This is the largest multiple of 6 that is less than 47. When you calculate the remainder, 47 minus 42 equals 5. Therefore, 6 goes into 47 seven times with a remainder of 5.
9 times with a remainder of 2