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50 percent dextrose solution and you need a 1 percent dextrose soultion. How do you figure that out?
Wiki User
∙ 14y ago
If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution.
If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.
Wiki User
∙ 14y ago
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Let's assume you have 1 L of the 37% solution by volume of chemical A. So your solution would contain 0.37 L of A & 0.63 L of water.0.37 L of A / (0.37 L of A + 0.63 L of water) = 37% solution of AObviously in order to dilute the solution to 2% we have to add water. Now we need to figure out how much. We'll call it X. So you set up the ratio as follows & solve for X.0.37 / (0.37 + 0.36 + X ) = 0.020.37 = 0.02 (1.00 + X)0.37 = 0.02 + 0.02X0.37 - 0.02 = 0.02 + 0.02X - 0.020.35 = 0.02X0.35/0.02 = XX = 17.5, so you would have to add 17.5 L of water to the originial 37% solution to dilute it to 2%.Obviously this answer will change depending on how much of the 37% solution you have to start with but the procedure to figure it out is still the same.
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