Volts by themselves are 0 amps. Volts cause current to flow, which is measured in amps. But there has to be a circuit, which is essentially a circle for the current to flow in. And current is usually limited by a load, which is any device that utilizes electrical energy. Without a load you have a short circuit which can allow hundreds or thousands of amps to flow until something burns up or a protective device trips, like a breaker or fuse.
600
6
600 miles = 965.6 kilometers.
600 thousands equal 6,000,000 tenths,
If the question means how many miles is 600 km, the answer is 372.82 (to 2 dp).
800 000 Watts / 600 Volts = 1333.3333333 Amps
The terminal strip's rating is 15 amps at 600 volts. It does not matter what the voltage is up to 600 volts, the maximum amperage allowed on the strip is 15 amps. It could be 15 amps at 12 volts or 15 amps at 600 volts or any voltage in between.
A milliamp (mA) is a unit of electricity (600 mA equals .6 amps). Converted to volts 600 ma equals .6 volts
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
600 This depends on the voltage Voltage x Amps = Watts ex. At 120 volts 5 amps WILL BE 600 watts But at 110 Volts (Some house voltage), it will be 550 watts And at 277 Volt (commercial-Industrial Voltage), it would be 1385 Watts If you know Watts (Like a 75w Incandescent Lamp) and the Voltage: Watts / Volts = Amps So 75w / 120v = 0.625a The last would be Watts / Amps = Volts 600w / 5a = 120v
13 amps should be a dedicated outlet since one outlet has a maximum capacity of 15 amps <<>> If the supply voltage is 120 volts then the amperage is I = W/E. Amps = Watts/Volts = 1450/120 = 12.08 amps.
It's the amps that are controlled by the breaker not the volts. You can have a 600 volt 15 amp breaker, you can have a 347 volt 15 amp breaker. The breaker will trip when you exceed 15 AMPS.
600 VDC.
Ohm's Law states Volts = Amps x Resistance. You would need to apply 600 volts across 3 ohm load to have 200 Amps flow in circuit. Not sure what you are really asking and why you mentioned 2 gauge.
Watts = Amps x Volts Assuming 115 Volts...do the math
varies, go out and check on top of battery, should have sticker that says cold cranking amps. all batteries should run 12.6 volts, do the math from that.watts = volts * amps , take the CCA (cold Cranking amps) number on the Battery and multiply it by 12.6No one answer, as there is no one car battery. Most are 12 volt batteries, but that can really be anywhere from about 13.2 to 11 volts. A standard large battery will have ABOUT 50 amps of current. Multiplying volts times amps equals watts. 12 x50= 600 watts. HOWEVER- you cannot draw that much power for more than a few seconds. Heat buildup would damage battery.